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Solve 8x āˆ’ 12 = 108

The solution of 8x āˆ’ 12 = 108 is x = 15.

The lines y = 8x āˆ’ 12 and y = 108 meet at x = 151012141618206080100120140160x = 15y = 8x āˆ’ 12y = 108
The lines y = 8x āˆ’ 12 and y = 108 meet at x = 15. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’12=1088x - 12 = 108
  2. 2

    Add 12 to both sides:

    8xāˆ’12+12=108+12 ⇒ 8x=1208x - 12 + 12 = 108 + 12 \ \Rightarrow\ 8x = 120
  3. 3

    Divide both sides by 8:

    8x8=1208 ⇒ x=15\frac{8x}{8} = \frac{120}{8} \ \Rightarrow\ x = 15
  4. 4

    Check: put x = 15 back into the equation.

    8ā‹…15āˆ’12=120āˆ’12=108āœ“8\cdot15 - 12 = 120 - 12 = 108 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 12 = 108\ \Rightarrow\ x = 15 \]
\[ 8x - 12 = 108 \]
\[ 8x - 12 + 12 = 108 + 12 \ \Rightarrow\ 8x = 120 \]
\[ \frac{8x}{8} = \frac{120}{8} \ \Rightarrow\ x = 15 \]
\[ 8\cdot15 - 12 = 120 - 12 = 108 \checkmark \]

Trying values of x in 8x āˆ’ 12 = 108

x8x āˆ’ 12Equals 108?
1392no
14100no
15108yes
16116no
17124no

Questions

What is x in 8x āˆ’ 12 = 108?

The solution of 8x āˆ’ 12 = 108 is x = 15.

How do you solve 8x āˆ’ 12 = 108?

Add 12 to both sides to get 8x = 120, then divide both sides by 8 to get x = 15.

How do I check the answer?

Replace x by 15: 8(15) āˆ’ 12 = 108, which is 108.

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