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Solve 8x āˆ’ 11 = 5

The solution of 8x āˆ’ 11 = 5 is x = 2.

The lines y = 8x āˆ’ 11 and y = 5 meet at x = 2-4-22468-40-20204060x = 2y = 8x āˆ’ 11y = 5
The lines y = 8x āˆ’ 11 and y = 5 meet at x = 2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’11=58x - 11 = 5
  2. 2

    Add 11 to both sides:

    8xāˆ’11+11=5+11 ⇒ 8x=168x - 11 + 11 = 5 + 11 \ \Rightarrow\ 8x = 16
  3. 3

    Divide both sides by 8:

    8x8=168 ⇒ x=2\frac{8x}{8} = \frac{16}{8} \ \Rightarrow\ x = 2
  4. 4

    Check: put x = 2 back into the equation.

    8ā‹…2āˆ’11=16āˆ’11=5āœ“8\cdot2 - 11 = 16 - 11 = 5 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 11 = 5\ \Rightarrow\ x = 2 \]
\[ 8x - 11 = 5 \]
\[ 8x - 11 + 11 = 5 + 11 \ \Rightarrow\ 8x = 16 \]
\[ \frac{8x}{8} = \frac{16}{8} \ \Rightarrow\ x = 2 \]
\[ 8\cdot2 - 11 = 16 - 11 = 5 \checkmark \]

Trying values of x in 8x āˆ’ 11 = 5

x8x āˆ’ 11Equals 5?
0-11no
1-3no
25yes
313no
421no

Questions

What is x in 8x āˆ’ 11 = 5?

The solution of 8x āˆ’ 11 = 5 is x = 2.

How do you solve 8x āˆ’ 11 = 5?

Add 11 to both sides to get 8x = 16, then divide both sides by 8 to get x = 2.

How do I check the answer?

Replace x by 2: 8(2) āˆ’ 11 = 5, which is 5.

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