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Solve 8x āˆ’ 11 = 109

The solution of 8x āˆ’ 11 = 109 is x = 15.

The lines y = 8x āˆ’ 11 and y = 109 meet at x = 151012141618206080100120140160x = 15y = 8x āˆ’ 11y = 109
The lines y = 8x āˆ’ 11 and y = 109 meet at x = 15. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’11=1098x - 11 = 109
  2. 2

    Add 11 to both sides:

    8xāˆ’11+11=109+11 ⇒ 8x=1208x - 11 + 11 = 109 + 11 \ \Rightarrow\ 8x = 120
  3. 3

    Divide both sides by 8:

    8x8=1208 ⇒ x=15\frac{8x}{8} = \frac{120}{8} \ \Rightarrow\ x = 15
  4. 4

    Check: put x = 15 back into the equation.

    8ā‹…15āˆ’11=120āˆ’11=109āœ“8\cdot15 - 11 = 120 - 11 = 109 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 11 = 109\ \Rightarrow\ x = 15 \]
\[ 8x - 11 = 109 \]
\[ 8x - 11 + 11 = 109 + 11 \ \Rightarrow\ 8x = 120 \]
\[ \frac{8x}{8} = \frac{120}{8} \ \Rightarrow\ x = 15 \]
\[ 8\cdot15 - 11 = 120 - 11 = 109 \checkmark \]

Trying values of x in 8x āˆ’ 11 = 109

x8x āˆ’ 11Equals 109?
1393no
14101no
15109yes
16117no
17125no

Questions

What is x in 8x āˆ’ 11 = 109?

The solution of 8x āˆ’ 11 = 109 is x = 15.

How do you solve 8x āˆ’ 11 = 109?

Add 11 to both sides to get 8x = 120, then divide both sides by 8 to get x = 15.

How do I check the answer?

Replace x by 15: 8(15) āˆ’ 11 = 109, which is 109.

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