Solve 8x − 1 = 7

The solution of 8x − 1 = 7 is x = 1.

8x - 1 = 7\ \Rightarrow\ x = 1

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The lines y = 8x − 1 and y = 7 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$8x - 1 = 7$
2
Add 1 to both sides:
$8x - 1 + 1 = 7 + 1 \ \Rightarrow\ 8x = 8$
3
Divide both sides by 8:
$\frac{8x}{8} = \frac{8}{8} \ \Rightarrow\ x = 1$
4
Check: put x = 1 back into the equation.
$8\cdot1 - 1 = 8 - 1 = 7 \checkmark$

LaTeX source of the formulas on this page

\[ 8x - 1 = 7\ \Rightarrow\ x = 1 \]
\[ 8x - 1 = 7 \]
\[ 8x - 1 + 1 = 7 + 1 \ \Rightarrow\ 8x = 8 \]
\[ \frac{8x}{8} = \frac{8}{8} \ \Rightarrow\ x = 1 \]
\[ 8\cdot1 - 1 = 8 - 1 = 7 \checkmark \]

Trying values of x in 8x − 1 = 7

x	8x − 1	Equals 7?
-1	-9	no
0	-1	no
1	7	yes
2	15	no
3	23	no

Questions

What is x in 8x − 1 = 7?

The solution of 8x − 1 = 7 is x = 1.

How do you solve 8x − 1 = 7?

Add 1 to both sides to get 8x = 8, then divide both sides by 8 to get x = 1.

How do I check the answer?

Replace x by 1: 8(1) − 1 = 7, which is 7.

Solve 8x − 1 = 7

How to work it out

Trying values of x in 8x − 1 = 7

Questions

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