Solve 7x + 7 = 35
The solution of 7x + 7 = 35 is x = 4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = 4 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 7 = 35\ \Rightarrow\ x = 4 \]
\[ 7x + 7 = 35 \]
\[ 7x + 7 - 7 = 35 - 7 \ \Rightarrow\ 7x = 28 \]
\[ \frac{7x}{7} = \frac{28}{7} \ \Rightarrow\ x = 4 \]
\[ 7\cdot4 + 7 = 28 + 7 = 35 \checkmark \]Trying values of x in 7x + 7 = 35
| x | 7x + 7 | Equals 35? |
|---|---|---|
| 2 | 21 | no |
| 3 | 28 | no |
| 4 | 35 | yes |
| 5 | 42 | no |
| 6 | 49 | no |
Questions
What is x in 7x + 7 = 35?
The solution of 7x + 7 = 35 is x = 4.
How do you solve 7x + 7 = 35?
Subtract 7 from both sides to get 7x = 28, then divide both sides by 7 to get x = 4.
How do I check the answer?
Replace x by 4: 7(4) + 7 = 35, which is 35.