Solve 7x + 6 = 118
The solution of 7x + 6 = 118 is x = 16.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 6 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = 16 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 6 = 118\ \Rightarrow\ x = 16 \]
\[ 7x + 6 = 118 \]
\[ 7x + 6 - 6 = 118 - 6 \ \Rightarrow\ 7x = 112 \]
\[ \frac{7x}{7} = \frac{112}{7} \ \Rightarrow\ x = 16 \]
\[ 7\cdot16 + 6 = 112 + 6 = 118 \checkmark \]Trying values of x in 7x + 6 = 118
| x | 7x + 6 | Equals 118? |
|---|---|---|
| 14 | 104 | no |
| 15 | 111 | no |
| 16 | 118 | yes |
| 17 | 125 | no |
| 18 | 132 | no |
Questions
What is x in 7x + 6 = 118?
The solution of 7x + 6 = 118 is x = 16.
How do you solve 7x + 6 = 118?
Subtract 6 from both sides to get 7x = 112, then divide both sides by 7 to get x = 16.
How do I check the answer?
Replace x by 16: 7(16) + 6 = 118, which is 118.