Solve 7x + 5 = 117
The solution of 7x + 5 = 117 is x = 16.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = 16 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 5 = 117\ \Rightarrow\ x = 16 \]
\[ 7x + 5 = 117 \]
\[ 7x + 5 - 5 = 117 - 5 \ \Rightarrow\ 7x = 112 \]
\[ \frac{7x}{7} = \frac{112}{7} \ \Rightarrow\ x = 16 \]
\[ 7\cdot16 + 5 = 112 + 5 = 117 \checkmark \]Trying values of x in 7x + 5 = 117
| x | 7x + 5 | Equals 117? |
|---|---|---|
| 14 | 103 | no |
| 15 | 110 | no |
| 16 | 117 | yes |
| 17 | 124 | no |
| 18 | 131 | no |
Questions
What is x in 7x + 5 = 117?
The solution of 7x + 5 = 117 is x = 16.
How do you solve 7x + 5 = 117?
Subtract 5 from both sides to get 7x = 112, then divide both sides by 7 to get x = 16.
How do I check the answer?
Replace x by 16: 7(16) + 5 = 117, which is 117.