Solve 7x + 3 = 80
The solution of 7x + 3 = 80 is x = 11.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 3 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = 11 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 3 = 80\ \Rightarrow\ x = 11 \]
\[ 7x + 3 = 80 \]
\[ 7x + 3 - 3 = 80 - 3 \ \Rightarrow\ 7x = 77 \]
\[ \frac{7x}{7} = \frac{77}{7} \ \Rightarrow\ x = 11 \]
\[ 7\cdot11 + 3 = 77 + 3 = 80 \checkmark \]Trying values of x in 7x + 3 = 80
| x | 7x + 3 | Equals 80? |
|---|---|---|
| 9 | 66 | no |
| 10 | 73 | no |
| 11 | 80 | yes |
| 12 | 87 | no |
| 13 | 94 | no |
Questions
What is x in 7x + 3 = 80?
The solution of 7x + 3 = 80 is x = 11.
How do you solve 7x + 3 = 80?
Subtract 3 from both sides to get 7x = 77, then divide both sides by 7 to get x = 11.
How do I check the answer?
Replace x by 11: 7(11) + 3 = 80, which is 80.