Solve 7x + 2 = ā33
The solution of 7x + 2 = ā33 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 2 = -33\ \Rightarrow\ x = -5 \]
\[ 7x + 2 = -33 \]
\[ 7x + 2 - 2 = -33 - 2 \ \Rightarrow\ 7x = -35 \]
\[ \frac{7x}{7} = \frac{-35}{7} \ \Rightarrow\ x = -5 \]
\[ 7\cdot(-5) + 2 = -35 + 2 = -33 \checkmark \]Trying values of x in 7x + 2 = ā33
| x | 7x + 2 | Equals -33? |
|---|---|---|
| -7 | -47 | no |
| -6 | -40 | no |
| -5 | -33 | yes |
| -4 | -26 | no |
| -3 | -19 | no |
Questions
What is x in 7x + 2 = ā33?
The solution of 7x + 2 = ā33 is x = -5.
How do you solve 7x + 2 = ā33?
Subtract 2 from both sides to get 7x = -35, then divide both sides by 7 to get x = -5.
How do I check the answer?
Replace x by -5: 7(-5) + 2 = -33, which is -33.