Solve 7x + 2 = ā19
The solution of 7x + 2 = ā19 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 2 = -19\ \Rightarrow\ x = -3 \]
\[ 7x + 2 = -19 \]
\[ 7x + 2 - 2 = -19 - 2 \ \Rightarrow\ 7x = -21 \]
\[ \frac{7x}{7} = \frac{-21}{7} \ \Rightarrow\ x = -3 \]
\[ 7\cdot(-3) + 2 = -21 + 2 = -19 \checkmark \]Trying values of x in 7x + 2 = ā19
| x | 7x + 2 | Equals -19? |
|---|---|---|
| -5 | -33 | no |
| -4 | -26 | no |
| -3 | -19 | yes |
| -2 | -12 | no |
| -1 | -5 | no |
Questions
What is x in 7x + 2 = ā19?
The solution of 7x + 2 = ā19 is x = -3.
How do you solve 7x + 2 = ā19?
Subtract 2 from both sides to get 7x = -21, then divide both sides by 7 to get x = -3.
How do I check the answer?
Replace x by -3: 7(-3) + 2 = -19, which is -19.