Solve 7x + 15 = 22
The solution of 7x + 15 = 22 is x = 1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = 1 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 15 = 22\ \Rightarrow\ x = 1 \]
\[ 7x + 15 = 22 \]
\[ 7x + 15 - 15 = 22 - 15 \ \Rightarrow\ 7x = 7 \]
\[ \frac{7x}{7} = \frac{7}{7} \ \Rightarrow\ x = 1 \]
\[ 7\cdot1 + 15 = 7 + 15 = 22 \checkmark \]Trying values of x in 7x + 15 = 22
| x | 7x + 15 | Equals 22? |
|---|---|---|
| -1 | 8 | no |
| 0 | 15 | no |
| 1 | 22 | yes |
| 2 | 29 | no |
| 3 | 36 | no |
Questions
What is x in 7x + 15 = 22?
The solution of 7x + 15 = 22 is x = 1.
How do you solve 7x + 15 = 22?
Subtract 15 from both sides to get 7x = 7, then divide both sides by 7 to get x = 1.
How do I check the answer?
Replace x by 1: 7(1) + 15 = 22, which is 22.