Solve 7x + 12 = 33
The solution of 7x + 12 = 33 is x = 3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = 3 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 12 = 33\ \Rightarrow\ x = 3 \]
\[ 7x + 12 = 33 \]
\[ 7x + 12 - 12 = 33 - 12 \ \Rightarrow\ 7x = 21 \]
\[ \frac{7x}{7} = \frac{21}{7} \ \Rightarrow\ x = 3 \]
\[ 7\cdot3 + 12 = 21 + 12 = 33 \checkmark \]Trying values of x in 7x + 12 = 33
| x | 7x + 12 | Equals 33? |
|---|---|---|
| 1 | 19 | no |
| 2 | 26 | no |
| 3 | 33 | yes |
| 4 | 40 | no |
| 5 | 47 | no |
Questions
What is x in 7x + 12 = 33?
The solution of 7x + 12 = 33 is x = 3.
How do you solve 7x + 12 = 33?
Subtract 12 from both sides to get 7x = 21, then divide both sides by 7 to get x = 3.
How do I check the answer?
Replace x by 3: 7(3) + 12 = 33, which is 33.