Solve 7x + 12 = 19

The solution of 7x + 12 = 19 is x = 1.

7x + 12 = 19\ \Rightarrow\ x = 1

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The lines y = 7x + 12 and y = 19 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
$7x + 12 = 19$
2
Subtract 12 from both sides:
$7x + 12 - 12 = 19 - 12 \ \Rightarrow\ 7x = 7$
3
Divide both sides by 7:
$\frac{7x}{7} = \frac{7}{7} \ \Rightarrow\ x = 1$
4
Check: put x = 1 back into the equation.
$7\cdot1 + 12 = 7 + 12 = 19 \checkmark$

LaTeX source of the formulas on this page

\[ 7x + 12 = 19\ \Rightarrow\ x = 1 \]
\[ 7x + 12 = 19 \]
\[ 7x + 12 - 12 = 19 - 12 \ \Rightarrow\ 7x = 7 \]
\[ \frac{7x}{7} = \frac{7}{7} \ \Rightarrow\ x = 1 \]
\[ 7\cdot1 + 12 = 7 + 12 = 19 \checkmark \]

Trying values of x in 7x + 12 = 19

x	7x + 12	Equals 19?
-1	5	no
0	12	no
1	19	yes
2	26	no
3	33	no

Questions

What is x in 7x + 12 = 19?

The solution of 7x + 12 = 19 is x = 1.

How do you solve 7x + 12 = 19?

Subtract 12 from both sides to get 7x = 7, then divide both sides by 7 to get x = 1.

How do I check the answer?

Replace x by 1: 7(1) + 12 = 19, which is 19.

Solve 7x + 12 = 19

How to work it out

Trying values of x in 7x + 12 = 19

Questions

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