Solve 7x + 1 = ā55
The solution of 7x + 1 = ā55 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 1 = -55\ \Rightarrow\ x = -8 \]
\[ 7x + 1 = -55 \]
\[ 7x + 1 - 1 = -55 - 1 \ \Rightarrow\ 7x = -56 \]
\[ \frac{7x}{7} = \frac{-56}{7} \ \Rightarrow\ x = -8 \]
\[ 7\cdot(-8) + 1 = -56 + 1 = -55 \checkmark \]Trying values of x in 7x + 1 = ā55
| x | 7x + 1 | Equals -55? |
|---|---|---|
| -10 | -69 | no |
| -9 | -62 | no |
| -8 | -55 | yes |
| -7 | -48 | no |
| -6 | -41 | no |
Questions
What is x in 7x + 1 = ā55?
The solution of 7x + 1 = ā55 is x = -8.
How do you solve 7x + 1 = ā55?
Subtract 1 from both sides to get 7x = -56, then divide both sides by 7 to get x = -8.
How do I check the answer?
Replace x by -8: 7(-8) + 1 = -55, which is -55.