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Solve 7x āˆ’ 7 = 0

The solution of 7x āˆ’ 7 = 0 is x = 1.

The lines y = 7x āˆ’ 7 and y = 0 meet at x = 1-4-2246-40-202040x = 1y = 7x āˆ’ 7y = 0
The lines y = 7x āˆ’ 7 and y = 0 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    7xāˆ’7=07x - 7 = 0
  2. 2

    Add 7 to both sides:

    7xāˆ’7+7=0+7 ⇒ 7x=77x - 7 + 7 = 0 + 7 \ \Rightarrow\ 7x = 7
  3. 3

    Divide both sides by 7:

    7x7=77 ⇒ x=1\frac{7x}{7} = \frac{7}{7} \ \Rightarrow\ x = 1
  4. 4

    Check: put x = 1 back into the equation.

    7ā‹…1āˆ’7=7āˆ’7=0āœ“7\cdot1 - 7 = 7 - 7 = 0 \checkmark
LaTeX source of the formulas on this page
\[ 7x - 7 = 0\ \Rightarrow\ x = 1 \]
\[ 7x - 7 = 0 \]
\[ 7x - 7 + 7 = 0 + 7 \ \Rightarrow\ 7x = 7 \]
\[ \frac{7x}{7} = \frac{7}{7} \ \Rightarrow\ x = 1 \]
\[ 7\cdot1 - 7 = 7 - 7 = 0 \checkmark \]

Trying values of x in 7x āˆ’ 7 = 0

x7x āˆ’ 7Equals 0?
-1-14no
0-7no
10yes
27no
314no

Questions

What is x in 7x āˆ’ 7 = 0?

The solution of 7x āˆ’ 7 = 0 is x = 1.

How do you solve 7x āˆ’ 7 = 0?

Add 7 to both sides to get 7x = 7, then divide both sides by 7 to get x = 1.

How do I check the answer?

Replace x by 1: 7(1) āˆ’ 7 = 0, which is 0.

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