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Solve 7x āˆ’ 15 = āˆ’57

The solution of 7x āˆ’ 15 = āˆ’57 is x = -6.

The lines y = 7x āˆ’ 15 and y = -57 meet at x = -6-12-10-8-6-4-2-100-80-60-40-20x = -6y = 7x āˆ’ 15y = -57
The lines y = 7x āˆ’ 15 and y = -57 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    7xāˆ’15=āˆ’577x - 15 = -57
  2. 2

    Add 15 to both sides:

    7xāˆ’15+15=āˆ’57+15 ⇒ 7x=āˆ’427x - 15 + 15 = -57 + 15 \ \Rightarrow\ 7x = -42
  3. 3

    Divide both sides by 7:

    7x7=āˆ’427 ⇒ x=āˆ’6\frac{7x}{7} = \frac{-42}{7} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    7ā‹…(āˆ’6)āˆ’15=āˆ’42āˆ’15=āˆ’57āœ“7\cdot(-6) - 15 = -42 - 15 = -57 \checkmark
LaTeX source of the formulas on this page
\[ 7x - 15 = -57\ \Rightarrow\ x = -6 \]
\[ 7x - 15 = -57 \]
\[ 7x - 15 + 15 = -57 + 15 \ \Rightarrow\ 7x = -42 \]
\[ \frac{7x}{7} = \frac{-42}{7} \ \Rightarrow\ x = -6 \]
\[ 7\cdot(-6) - 15 = -42 - 15 = -57 \checkmark \]

Trying values of x in 7x āˆ’ 15 = āˆ’57

x7x āˆ’ 15Equals -57?
-8-71no
-7-64no
-6-57yes
-5-50no
-4-43no

Questions

What is x in 7x āˆ’ 15 = āˆ’57?

The solution of 7x āˆ’ 15 = āˆ’57 is x = -6.

How do you solve 7x āˆ’ 15 = āˆ’57?

Add 15 to both sides to get 7x = -42, then divide both sides by 7 to get x = -6.

How do I check the answer?

Replace x by -6: 7(-6) āˆ’ 15 = -57, which is -57.

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    Solve 7x āˆ’ 15 = āˆ’57: x = -6 (steps and check) | WordGPT