Solve 7x − 15 = 41

The solution of 7x − 15 = 41 is x = 8.

7x - 15 = 41\ \Rightarrow\ x = 8

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The lines y = 7x − 15 and y = 41 meet at x = 8. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$7x - 15 = 41$
2
Add 15 to both sides:
$7x - 15 + 15 = 41 + 15 \ \Rightarrow\ 7x = 56$
3
Divide both sides by 7:
$\frac{7x}{7} = \frac{56}{7} \ \Rightarrow\ x = 8$
4
Check: put x = 8 back into the equation.
$7\cdot8 - 15 = 56 - 15 = 41 \checkmark$

LaTeX source of the formulas on this page

\[ 7x - 15 = 41\ \Rightarrow\ x = 8 \]
\[ 7x - 15 = 41 \]
\[ 7x - 15 + 15 = 41 + 15 \ \Rightarrow\ 7x = 56 \]
\[ \frac{7x}{7} = \frac{56}{7} \ \Rightarrow\ x = 8 \]
\[ 7\cdot8 - 15 = 56 - 15 = 41 \checkmark \]

Trying values of x in 7x − 15 = 41

x	7x − 15	Equals 41?
6	27	no
7	34	no
8	41	yes
9	48	no
10	55	no

Questions

What is x in 7x − 15 = 41?

The solution of 7x − 15 = 41 is x = 8.

How do you solve 7x − 15 = 41?

Add 15 to both sides to get 7x = 56, then divide both sides by 7 to get x = 8.

How do I check the answer?

Replace x by 8: 7(8) − 15 = 41, which is 41.

Solve 7x − 15 = 41

How to work it out

Trying values of x in 7x − 15 = 41

Questions

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