Solve 7x − 15 = 118

The solution of 7x − 15 = 118 is x = 19.

7x - 15 = 118\ \Rightarrow\ x = 19

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The lines y = 7x − 15 and y = 118 meet at x = 19. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$7x - 15 = 118$
2
Add 15 to both sides:
$7x - 15 + 15 = 118 + 15 \ \Rightarrow\ 7x = 133$
3
Divide both sides by 7:
$\frac{7x}{7} = \frac{133}{7} \ \Rightarrow\ x = 19$
4
Check: put x = 19 back into the equation.
$7\cdot19 - 15 = 133 - 15 = 118 \checkmark$

LaTeX source of the formulas on this page

\[ 7x - 15 = 118\ \Rightarrow\ x = 19 \]
\[ 7x - 15 = 118 \]
\[ 7x - 15 + 15 = 118 + 15 \ \Rightarrow\ 7x = 133 \]
\[ \frac{7x}{7} = \frac{133}{7} \ \Rightarrow\ x = 19 \]
\[ 7\cdot19 - 15 = 133 - 15 = 118 \checkmark \]

Trying values of x in 7x − 15 = 118

x	7x − 15	Equals 118?
17	104	no
18	111	no
19	118	yes
20	125	no
21	132	no

Questions

What is x in 7x − 15 = 118?

The solution of 7x − 15 = 118 is x = 19.

How do you solve 7x − 15 = 118?

Add 15 to both sides to get 7x = 133, then divide both sides by 7 to get x = 19.

How do I check the answer?

Replace x by 19: 7(19) − 15 = 118, which is 118.

Solve 7x − 15 = 118

How to work it out

Trying values of x in 7x − 15 = 118

Questions

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