Solve 7x ā 13 = ā48
The solution of 7x ā 13 = ā48 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 13 to both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 7x - 13 = -48\ \Rightarrow\ x = -5 \]
\[ 7x - 13 = -48 \]
\[ 7x - 13 + 13 = -48 + 13 \ \Rightarrow\ 7x = -35 \]
\[ \frac{7x}{7} = \frac{-35}{7} \ \Rightarrow\ x = -5 \]
\[ 7\cdot(-5) - 13 = -35 - 13 = -48 \checkmark \]Trying values of x in 7x ā 13 = ā48
| x | 7x ā 13 | Equals -48? |
|---|---|---|
| -7 | -62 | no |
| -6 | -55 | no |
| -5 | -48 | yes |
| -4 | -41 | no |
| -3 | -34 | no |
Questions
What is x in 7x ā 13 = ā48?
The solution of 7x ā 13 = ā48 is x = -5.
How do you solve 7x ā 13 = ā48?
Add 13 to both sides to get 7x = -35, then divide both sides by 7 to get x = -5.
How do I check the answer?
Replace x by -5: 7(-5) ā 13 = -48, which is -48.