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Solve 7x āˆ’ 12 = āˆ’40

The solution of 7x āˆ’ 12 = āˆ’40 is x = -4.

The lines y = 7x āˆ’ 12 and y = -40 meet at x = -4-10-8-6-4-22-80-60-40-20x = -4y = 7x āˆ’ 12y = -40
The lines y = 7x āˆ’ 12 and y = -40 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    7xāˆ’12=āˆ’407x - 12 = -40
  2. 2

    Add 12 to both sides:

    7xāˆ’12+12=āˆ’40+12 ⇒ 7x=āˆ’287x - 12 + 12 = -40 + 12 \ \Rightarrow\ 7x = -28
  3. 3

    Divide both sides by 7:

    7x7=āˆ’287 ⇒ x=āˆ’4\frac{7x}{7} = \frac{-28}{7} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    7ā‹…(āˆ’4)āˆ’12=āˆ’28āˆ’12=āˆ’40āœ“7\cdot(-4) - 12 = -28 - 12 = -40 \checkmark
LaTeX source of the formulas on this page
\[ 7x - 12 = -40\ \Rightarrow\ x = -4 \]
\[ 7x - 12 = -40 \]
\[ 7x - 12 + 12 = -40 + 12 \ \Rightarrow\ 7x = -28 \]
\[ \frac{7x}{7} = \frac{-28}{7} \ \Rightarrow\ x = -4 \]
\[ 7\cdot(-4) - 12 = -28 - 12 = -40 \checkmark \]

Trying values of x in 7x āˆ’ 12 = āˆ’40

x7x āˆ’ 12Equals -40?
-6-54no
-5-47no
-4-40yes
-3-33no
-2-26no

Questions

What is x in 7x āˆ’ 12 = āˆ’40?

The solution of 7x āˆ’ 12 = āˆ’40 is x = -4.

How do you solve 7x āˆ’ 12 = āˆ’40?

Add 12 to both sides to get 7x = -28, then divide both sides by 7 to get x = -4.

How do I check the answer?

Replace x by -4: 7(-4) āˆ’ 12 = -40, which is -40.

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    Solve 7x āˆ’ 12 = āˆ’40: x = -4 (steps and check) | WordGPT