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Solve 7x āˆ’ 11 = āˆ’32

The solution of 7x āˆ’ 11 = āˆ’32 is x = -3.

The lines y = 7x āˆ’ 11 and y = -32 meet at x = -3-8-6-4-22-80-60-40-20x = -3y = 7x āˆ’ 11y = -32
The lines y = 7x āˆ’ 11 and y = -32 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    7xāˆ’11=āˆ’327x - 11 = -32
  2. 2

    Add 11 to both sides:

    7xāˆ’11+11=āˆ’32+11 ⇒ 7x=āˆ’217x - 11 + 11 = -32 + 11 \ \Rightarrow\ 7x = -21
  3. 3

    Divide both sides by 7:

    7x7=āˆ’217 ⇒ x=āˆ’3\frac{7x}{7} = \frac{-21}{7} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    7ā‹…(āˆ’3)āˆ’11=āˆ’21āˆ’11=āˆ’32āœ“7\cdot(-3) - 11 = -21 - 11 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 7x - 11 = -32\ \Rightarrow\ x = -3 \]
\[ 7x - 11 = -32 \]
\[ 7x - 11 + 11 = -32 + 11 \ \Rightarrow\ 7x = -21 \]
\[ \frac{7x}{7} = \frac{-21}{7} \ \Rightarrow\ x = -3 \]
\[ 7\cdot(-3) - 11 = -21 - 11 = -32 \checkmark \]

Trying values of x in 7x āˆ’ 11 = āˆ’32

x7x āˆ’ 11Equals -32?
-5-46no
-4-39no
-3-32yes
-2-25no
-1-18no

Questions

What is x in 7x āˆ’ 11 = āˆ’32?

The solution of 7x āˆ’ 11 = āˆ’32 is x = -3.

How do you solve 7x āˆ’ 11 = āˆ’32?

Add 11 to both sides to get 7x = -21, then divide both sides by 7 to get x = -3.

How do I check the answer?

Replace x by -3: 7(-3) āˆ’ 11 = -32, which is -32.

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    Solve 7x āˆ’ 11 = āˆ’32: x = -3 (steps and check) | WordGPT