Solve 6x + 8 = ā40
The solution of 6x + 8 = ā40 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 8 = -40\ \Rightarrow\ x = -8 \]
\[ 6x + 8 = -40 \]
\[ 6x + 8 - 8 = -40 - 8 \ \Rightarrow\ 6x = -48 \]
\[ \frac{6x}{6} = \frac{-48}{6} \ \Rightarrow\ x = -8 \]
\[ 6\cdot(-8) + 8 = -48 + 8 = -40 \checkmark \]Trying values of x in 6x + 8 = ā40
| x | 6x + 8 | Equals -40? |
|---|---|---|
| -10 | -52 | no |
| -9 | -46 | no |
| -8 | -40 | yes |
| -7 | -34 | no |
| -6 | -28 | no |
Questions
What is x in 6x + 8 = ā40?
The solution of 6x + 8 = ā40 is x = -8.
How do you solve 6x + 8 = ā40?
Subtract 8 from both sides to get 6x = -48, then divide both sides by 6 to get x = -8.
How do I check the answer?
Replace x by -8: 6(-8) + 8 = -40, which is -40.