Solve 6x + 8 = ā4
The solution of 6x + 8 = ā4 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 8 = -4\ \Rightarrow\ x = -2 \]
\[ 6x + 8 = -4 \]
\[ 6x + 8 - 8 = -4 - 8 \ \Rightarrow\ 6x = -12 \]
\[ \frac{6x}{6} = \frac{-12}{6} \ \Rightarrow\ x = -2 \]
\[ 6\cdot(-2) + 8 = -12 + 8 = -4 \checkmark \]Trying values of x in 6x + 8 = ā4
| x | 6x + 8 | Equals -4? |
|---|---|---|
| -4 | -16 | no |
| -3 | -10 | no |
| -2 | -4 | yes |
| -1 | 2 | no |
| 0 | 8 | no |
Questions
What is x in 6x + 8 = ā4?
The solution of 6x + 8 = ā4 is x = -2.
How do you solve 6x + 8 = ā4?
Subtract 8 from both sides to get 6x = -12, then divide both sides by 6 to get x = -2.
How do I check the answer?
Replace x by -2: 6(-2) + 8 = -4, which is -4.