Solve 6x + 7 = 19
The solution of 6x + 7 = 19 is x = 2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = 2 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 7 = 19\ \Rightarrow\ x = 2 \]
\[ 6x + 7 = 19 \]
\[ 6x + 7 - 7 = 19 - 7 \ \Rightarrow\ 6x = 12 \]
\[ \frac{6x}{6} = \frac{12}{6} \ \Rightarrow\ x = 2 \]
\[ 6\cdot2 + 7 = 12 + 7 = 19 \checkmark \]Trying values of x in 6x + 7 = 19
| x | 6x + 7 | Equals 19? |
|---|---|---|
| 0 | 7 | no |
| 1 | 13 | no |
| 2 | 19 | yes |
| 3 | 25 | no |
| 4 | 31 | no |
Questions
What is x in 6x + 7 = 19?
The solution of 6x + 7 = 19 is x = 2.
How do you solve 6x + 7 = 19?
Subtract 7 from both sides to get 6x = 12, then divide both sides by 6 to get x = 2.
How do I check the answer?
Replace x by 2: 6(2) + 7 = 19, which is 19.