Solve 6x + 6 = 78
The solution of 6x + 6 = 78 is x = 12.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 6 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = 12 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 6 = 78\ \Rightarrow\ x = 12 \]
\[ 6x + 6 = 78 \]
\[ 6x + 6 - 6 = 78 - 6 \ \Rightarrow\ 6x = 72 \]
\[ \frac{6x}{6} = \frac{72}{6} \ \Rightarrow\ x = 12 \]
\[ 6\cdot12 + 6 = 72 + 6 = 78 \checkmark \]Trying values of x in 6x + 6 = 78
| x | 6x + 6 | Equals 78? |
|---|---|---|
| 10 | 66 | no |
| 11 | 72 | no |
| 12 | 78 | yes |
| 13 | 84 | no |
| 14 | 90 | no |
Questions
What is x in 6x + 6 = 78?
The solution of 6x + 6 = 78 is x = 12.
How do you solve 6x + 6 = 78?
Subtract 6 from both sides to get 6x = 72, then divide both sides by 6 to get x = 12.
How do I check the answer?
Replace x by 12: 6(12) + 6 = 78, which is 78.