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Solve 6x + 4 = āˆ’32

The solution of 6x + 4 = āˆ’32 is x = -6.

The lines y = 6x + 4 and y = -32 meet at x = -6-12-10-8-6-4-2-70-60-50-40-30-20-1010x = -6y = 6x + 4y = -32
The lines y = 6x + 4 and y = -32 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+4=āˆ’326x + 4 = -32
  2. 2

    Subtract 4 from both sides:

    6x+4āˆ’4=āˆ’32āˆ’4 ⇒ 6x=āˆ’366x + 4 - 4 = -32 - 4 \ \Rightarrow\ 6x = -36
  3. 3

    Divide both sides by 6:

    6x6=āˆ’366 ⇒ x=āˆ’6\frac{6x}{6} = \frac{-36}{6} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    6ā‹…(āˆ’6)+4=āˆ’36+4=āˆ’32āœ“6\cdot(-6) + 4 = -36 + 4 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 4 = -32\ \Rightarrow\ x = -6 \]
\[ 6x + 4 = -32 \]
\[ 6x + 4 - 4 = -32 - 4 \ \Rightarrow\ 6x = -36 \]
\[ \frac{6x}{6} = \frac{-36}{6} \ \Rightarrow\ x = -6 \]
\[ 6\cdot(-6) + 4 = -36 + 4 = -32 \checkmark \]

Trying values of x in 6x + 4 = āˆ’32

x6x + 4Equals -32?
-8-44no
-7-38no
-6-32yes
-5-26no
-4-20no

Questions

What is x in 6x + 4 = āˆ’32?

The solution of 6x + 4 = āˆ’32 is x = -6.

How do you solve 6x + 4 = āˆ’32?

Subtract 4 from both sides to get 6x = -36, then divide both sides by 6 to get x = -6.

How do I check the answer?

Replace x by -6: 6(-6) + 4 = -32, which is -32.

Similar equations

    Solve 6x + 4 = āˆ’32: x = -6 (steps and check) | WordGPT