Solve 6x + 3 = ā33
The solution of 6x + 3 = ā33 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 3 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 3 = -33\ \Rightarrow\ x = -6 \]
\[ 6x + 3 = -33 \]
\[ 6x + 3 - 3 = -33 - 3 \ \Rightarrow\ 6x = -36 \]
\[ \frac{6x}{6} = \frac{-36}{6} \ \Rightarrow\ x = -6 \]
\[ 6\cdot(-6) + 3 = -36 + 3 = -33 \checkmark \]Trying values of x in 6x + 3 = ā33
| x | 6x + 3 | Equals -33? |
|---|---|---|
| -8 | -45 | no |
| -7 | -39 | no |
| -6 | -33 | yes |
| -5 | -27 | no |
| -4 | -21 | no |
Questions
What is x in 6x + 3 = ā33?
The solution of 6x + 3 = ā33 is x = -6.
How do you solve 6x + 3 = ā33?
Subtract 3 from both sides to get 6x = -36, then divide both sides by 6 to get x = -6.
How do I check the answer?
Replace x by -6: 6(-6) + 3 = -33, which is -33.