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Solve 6x + 2 = āˆ’58

The solution of 6x + 2 = āˆ’58 is x = -10.

The lines y = 6x + 2 and y = -58 meet at x = -10-16-14-12-10-8-6-4-100-90-80-70-60-50-40-30-20x = -10y = 6x + 2y = -58
The lines y = 6x + 2 and y = -58 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+2=āˆ’586x + 2 = -58
  2. 2

    Subtract 2 from both sides:

    6x+2āˆ’2=āˆ’58āˆ’2 ⇒ 6x=āˆ’606x + 2 - 2 = -58 - 2 \ \Rightarrow\ 6x = -60
  3. 3

    Divide both sides by 6:

    6x6=āˆ’606 ⇒ x=āˆ’10\frac{6x}{6} = \frac{-60}{6} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    6ā‹…(āˆ’10)+2=āˆ’60+2=āˆ’58āœ“6\cdot(-10) + 2 = -60 + 2 = -58 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 2 = -58\ \Rightarrow\ x = -10 \]
\[ 6x + 2 = -58 \]
\[ 6x + 2 - 2 = -58 - 2 \ \Rightarrow\ 6x = -60 \]
\[ \frac{6x}{6} = \frac{-60}{6} \ \Rightarrow\ x = -10 \]
\[ 6\cdot(-10) + 2 = -60 + 2 = -58 \checkmark \]

Trying values of x in 6x + 2 = āˆ’58

x6x + 2Equals -58?
-12-70no
-11-64no
-10-58yes
-9-52no
-8-46no

Questions

What is x in 6x + 2 = āˆ’58?

The solution of 6x + 2 = āˆ’58 is x = -10.

How do you solve 6x + 2 = āˆ’58?

Subtract 2 from both sides to get 6x = -60, then divide both sides by 6 to get x = -10.

How do I check the answer?

Replace x by -10: 6(-10) + 2 = -58, which is -58.

Similar equations

    Solve 6x + 2 = āˆ’58: x = -10 (steps and check) | WordGPT