Solve 6x + 2 = 68
The solution of 6x + 2 = 68 is x = 11.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = 11 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 2 = 68\ \Rightarrow\ x = 11 \]
\[ 6x + 2 = 68 \]
\[ 6x + 2 - 2 = 68 - 2 \ \Rightarrow\ 6x = 66 \]
\[ \frac{6x}{6} = \frac{66}{6} \ \Rightarrow\ x = 11 \]
\[ 6\cdot11 + 2 = 66 + 2 = 68 \checkmark \]Trying values of x in 6x + 2 = 68
| x | 6x + 2 | Equals 68? |
|---|---|---|
| 9 | 56 | no |
| 10 | 62 | no |
| 11 | 68 | yes |
| 12 | 74 | no |
| 13 | 80 | no |
Questions
What is x in 6x + 2 = 68?
The solution of 6x + 2 = 68 is x = 11.
How do you solve 6x + 2 = 68?
Subtract 2 from both sides to get 6x = 66, then divide both sides by 6 to get x = 11.
How do I check the answer?
Replace x by 11: 6(11) + 2 = 68, which is 68.