Solve 6x + 15 = 33
The solution of 6x + 15 = 33 is x = 3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = 3 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 15 = 33\ \Rightarrow\ x = 3 \]
\[ 6x + 15 = 33 \]
\[ 6x + 15 - 15 = 33 - 15 \ \Rightarrow\ 6x = 18 \]
\[ \frac{6x}{6} = \frac{18}{6} \ \Rightarrow\ x = 3 \]
\[ 6\cdot3 + 15 = 18 + 15 = 33 \checkmark \]Trying values of x in 6x + 15 = 33
| x | 6x + 15 | Equals 33? |
|---|---|---|
| 1 | 21 | no |
| 2 | 27 | no |
| 3 | 33 | yes |
| 4 | 39 | no |
| 5 | 45 | no |
Questions
What is x in 6x + 15 = 33?
The solution of 6x + 15 = 33 is x = 3.
How do you solve 6x + 15 = 33?
Subtract 15 from both sides to get 6x = 18, then divide both sides by 6 to get x = 3.
How do I check the answer?
Replace x by 3: 6(3) + 15 = 33, which is 33.