Solve 6x + 11 = ā43
The solution of 6x + 11 = ā43 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 11 = -43\ \Rightarrow\ x = -9 \]
\[ 6x + 11 = -43 \]
\[ 6x + 11 - 11 = -43 - 11 \ \Rightarrow\ 6x = -54 \]
\[ \frac{6x}{6} = \frac{-54}{6} \ \Rightarrow\ x = -9 \]
\[ 6\cdot(-9) + 11 = -54 + 11 = -43 \checkmark \]Trying values of x in 6x + 11 = ā43
| x | 6x + 11 | Equals -43? |
|---|---|---|
| -11 | -55 | no |
| -10 | -49 | no |
| -9 | -43 | yes |
| -8 | -37 | no |
| -7 | -31 | no |
Questions
What is x in 6x + 11 = ā43?
The solution of 6x + 11 = ā43 is x = -9.
How do you solve 6x + 11 = ā43?
Subtract 11 from both sides to get 6x = -54, then divide both sides by 6 to get x = -9.
How do I check the answer?
Replace x by -9: 6(-9) + 11 = -43, which is -43.