Solve 6x + 11 = ā19
The solution of 6x + 11 = ā19 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 11 = -19\ \Rightarrow\ x = -5 \]
\[ 6x + 11 = -19 \]
\[ 6x + 11 - 11 = -19 - 11 \ \Rightarrow\ 6x = -30 \]
\[ \frac{6x}{6} = \frac{-30}{6} \ \Rightarrow\ x = -5 \]
\[ 6\cdot(-5) + 11 = -30 + 11 = -19 \checkmark \]Trying values of x in 6x + 11 = ā19
| x | 6x + 11 | Equals -19? |
|---|---|---|
| -7 | -31 | no |
| -6 | -25 | no |
| -5 | -19 | yes |
| -4 | -13 | no |
| -3 | -7 | no |
Questions
What is x in 6x + 11 = ā19?
The solution of 6x + 11 = ā19 is x = -5.
How do you solve 6x + 11 = ā19?
Subtract 11 from both sides to get 6x = -30, then divide both sides by 6 to get x = -5.
How do I check the answer?
Replace x by -5: 6(-5) + 11 = -19, which is -19.