Solve 6x + 11 = 47
The solution of 6x + 11 = 47 is x = 6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = 6 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 11 = 47\ \Rightarrow\ x = 6 \]
\[ 6x + 11 = 47 \]
\[ 6x + 11 - 11 = 47 - 11 \ \Rightarrow\ 6x = 36 \]
\[ \frac{6x}{6} = \frac{36}{6} \ \Rightarrow\ x = 6 \]
\[ 6\cdot6 + 11 = 36 + 11 = 47 \checkmark \]Trying values of x in 6x + 11 = 47
| x | 6x + 11 | Equals 47? |
|---|---|---|
| 4 | 35 | no |
| 5 | 41 | no |
| 6 | 47 | yes |
| 7 | 53 | no |
| 8 | 59 | no |
Questions
What is x in 6x + 11 = 47?
The solution of 6x + 11 = 47 is x = 6.
How do you solve 6x + 11 = 47?
Subtract 11 from both sides to get 6x = 36, then divide both sides by 6 to get x = 6.
How do I check the answer?
Replace x by 6: 6(6) + 11 = 47, which is 47.