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Solve 6x + 1 = āˆ’41

The solution of 6x + 1 = āˆ’41 is x = -7.

The lines y = 6x + 1 and y = -41 meet at x = -7-12-10-8-6-4-2-80-70-60-50-40-30-20-10x = -7y = 6x + 1y = -41
The lines y = 6x + 1 and y = -41 meet at x = -7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+1=āˆ’416x + 1 = -41
  2. 2

    Subtract 1 from both sides:

    6x+1āˆ’1=āˆ’41āˆ’1 ⇒ 6x=āˆ’426x + 1 - 1 = -41 - 1 \ \Rightarrow\ 6x = -42
  3. 3

    Divide both sides by 6:

    6x6=āˆ’426 ⇒ x=āˆ’7\frac{6x}{6} = \frac{-42}{6} \ \Rightarrow\ x = -7
  4. 4

    Check: put x = -7 back into the equation.

    6ā‹…(āˆ’7)+1=āˆ’42+1=āˆ’41āœ“6\cdot(-7) + 1 = -42 + 1 = -41 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 1 = -41\ \Rightarrow\ x = -7 \]
\[ 6x + 1 = -41 \]
\[ 6x + 1 - 1 = -41 - 1 \ \Rightarrow\ 6x = -42 \]
\[ \frac{6x}{6} = \frac{-42}{6} \ \Rightarrow\ x = -7 \]
\[ 6\cdot(-7) + 1 = -42 + 1 = -41 \checkmark \]

Trying values of x in 6x + 1 = āˆ’41

x6x + 1Equals -41?
-9-53no
-8-47no
-7-41yes
-6-35no
-5-29no

Questions

What is x in 6x + 1 = āˆ’41?

The solution of 6x + 1 = āˆ’41 is x = -7.

How do you solve 6x + 1 = āˆ’41?

Subtract 1 from both sides to get 6x = -42, then divide both sides by 6 to get x = -7.

How do I check the answer?

Replace x by -7: 6(-7) + 1 = -41, which is -41.

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    Solve 6x + 1 = āˆ’41: x = -7 (steps and check) | WordGPT