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Solve 6x + 1 = āˆ’29

The solution of 6x + 1 = āˆ’29 is x = -5.

The lines y = 6x + 1 and y = -29 meet at x = -5-10-8-6-4-2-70-60-50-40-30-20-1010x = -5y = 6x + 1y = -29
The lines y = 6x + 1 and y = -29 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+1=āˆ’296x + 1 = -29
  2. 2

    Subtract 1 from both sides:

    6x+1āˆ’1=āˆ’29āˆ’1 ⇒ 6x=āˆ’306x + 1 - 1 = -29 - 1 \ \Rightarrow\ 6x = -30
  3. 3

    Divide both sides by 6:

    6x6=āˆ’306 ⇒ x=āˆ’5\frac{6x}{6} = \frac{-30}{6} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    6ā‹…(āˆ’5)+1=āˆ’30+1=āˆ’29āœ“6\cdot(-5) + 1 = -30 + 1 = -29 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 1 = -29\ \Rightarrow\ x = -5 \]
\[ 6x + 1 = -29 \]
\[ 6x + 1 - 1 = -29 - 1 \ \Rightarrow\ 6x = -30 \]
\[ \frac{6x}{6} = \frac{-30}{6} \ \Rightarrow\ x = -5 \]
\[ 6\cdot(-5) + 1 = -30 + 1 = -29 \checkmark \]

Trying values of x in 6x + 1 = āˆ’29

x6x + 1Equals -29?
-7-41no
-6-35no
-5-29yes
-4-23no
-3-17no

Questions

What is x in 6x + 1 = āˆ’29?

The solution of 6x + 1 = āˆ’29 is x = -5.

How do you solve 6x + 1 = āˆ’29?

Subtract 1 from both sides to get 6x = -30, then divide both sides by 6 to get x = -5.

How do I check the answer?

Replace x by -5: 6(-5) + 1 = -29, which is -29.

Similar equations

    Solve 6x + 1 = āˆ’29: x = -5 (steps and check) | WordGPT