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Solve 6x + 1 = āˆ’17

The solution of 6x + 1 = āˆ’17 is x = -3.

The lines y = 6x + 1 and y = -17 meet at x = -3-8-6-4-22-60-50-40-30-20-101020x = -3y = 6x + 1y = -17
The lines y = 6x + 1 and y = -17 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+1=āˆ’176x + 1 = -17
  2. 2

    Subtract 1 from both sides:

    6x+1āˆ’1=āˆ’17āˆ’1 ⇒ 6x=āˆ’186x + 1 - 1 = -17 - 1 \ \Rightarrow\ 6x = -18
  3. 3

    Divide both sides by 6:

    6x6=āˆ’186 ⇒ x=āˆ’3\frac{6x}{6} = \frac{-18}{6} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    6ā‹…(āˆ’3)+1=āˆ’18+1=āˆ’17āœ“6\cdot(-3) + 1 = -18 + 1 = -17 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 1 = -17\ \Rightarrow\ x = -3 \]
\[ 6x + 1 = -17 \]
\[ 6x + 1 - 1 = -17 - 1 \ \Rightarrow\ 6x = -18 \]
\[ \frac{6x}{6} = \frac{-18}{6} \ \Rightarrow\ x = -3 \]
\[ 6\cdot(-3) + 1 = -18 + 1 = -17 \checkmark \]

Trying values of x in 6x + 1 = āˆ’17

x6x + 1Equals -17?
-5-29no
-4-23no
-3-17yes
-2-11no
-1-5no

Questions

What is x in 6x + 1 = āˆ’17?

The solution of 6x + 1 = āˆ’17 is x = -3.

How do you solve 6x + 1 = āˆ’17?

Subtract 1 from both sides to get 6x = -18, then divide both sides by 6 to get x = -3.

How do I check the answer?

Replace x by -3: 6(-3) + 1 = -17, which is -17.

Similar equations

    Solve 6x + 1 = āˆ’17: x = -3 (steps and check) | WordGPT