Solve 6x + 1 = 7
The solution of 6x + 1 = 7 is x = 1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = 1 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 1 = 7\ \Rightarrow\ x = 1 \]
\[ 6x + 1 = 7 \]
\[ 6x + 1 - 1 = 7 - 1 \ \Rightarrow\ 6x = 6 \]
\[ \frac{6x}{6} = \frac{6}{6} \ \Rightarrow\ x = 1 \]
\[ 6\cdot1 + 1 = 6 + 1 = 7 \checkmark \]Trying values of x in 6x + 1 = 7
| x | 6x + 1 | Equals 7? |
|---|---|---|
| -1 | -5 | no |
| 0 | 1 | no |
| 1 | 7 | yes |
| 2 | 13 | no |
| 3 | 19 | no |
Questions
What is x in 6x + 1 = 7?
The solution of 6x + 1 = 7 is x = 1.
How do you solve 6x + 1 = 7?
Subtract 1 from both sides to get 6x = 6, then divide both sides by 6 to get x = 1.
How do I check the answer?
Replace x by 1: 6(1) + 1 = 7, which is 7.