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Solve 6x āˆ’ 15 = āˆ’9

The solution of 6x āˆ’ 15 = āˆ’9 is x = 1.

The lines y = 6x āˆ’ 15 and y = -9 meet at x = 1-4-2246-50-40-30-20-10102030x = 1y = 6x āˆ’ 15y = -9
The lines y = 6x āˆ’ 15 and y = -9 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    6xāˆ’15=āˆ’96x - 15 = -9
  2. 2

    Add 15 to both sides:

    6xāˆ’15+15=āˆ’9+15 ⇒ 6x=66x - 15 + 15 = -9 + 15 \ \Rightarrow\ 6x = 6
  3. 3

    Divide both sides by 6:

    6x6=66 ⇒ x=1\frac{6x}{6} = \frac{6}{6} \ \Rightarrow\ x = 1
  4. 4

    Check: put x = 1 back into the equation.

    6ā‹…1āˆ’15=6āˆ’15=āˆ’9āœ“6\cdot1 - 15 = 6 - 15 = -9 \checkmark
LaTeX source of the formulas on this page
\[ 6x - 15 = -9\ \Rightarrow\ x = 1 \]
\[ 6x - 15 = -9 \]
\[ 6x - 15 + 15 = -9 + 15 \ \Rightarrow\ 6x = 6 \]
\[ \frac{6x}{6} = \frac{6}{6} \ \Rightarrow\ x = 1 \]
\[ 6\cdot1 - 15 = 6 - 15 = -9 \checkmark \]

Trying values of x in 6x āˆ’ 15 = āˆ’9

x6x āˆ’ 15Equals -9?
-1-21no
0-15no
1-9yes
2-3no
33no

Questions

What is x in 6x āˆ’ 15 = āˆ’9?

The solution of 6x āˆ’ 15 = āˆ’9 is x = 1.

How do you solve 6x āˆ’ 15 = āˆ’9?

Add 15 to both sides to get 6x = 6, then divide both sides by 6 to get x = 1.

How do I check the answer?

Replace x by 1: 6(1) āˆ’ 15 = -9, which is -9.

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    Solve 6x āˆ’ 15 = āˆ’9: x = 1 (steps and check) | WordGPT