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Solve 6x āˆ’ 12 = āˆ’42

The solution of 6x āˆ’ 12 = āˆ’42 is x = -5.

The lines y = 6x āˆ’ 12 and y = -42 meet at x = -5-10-8-6-4-2-80-70-60-50-40-30-20-10x = -5y = 6x āˆ’ 12y = -42
The lines y = 6x āˆ’ 12 and y = -42 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    6xāˆ’12=āˆ’426x - 12 = -42
  2. 2

    Add 12 to both sides:

    6xāˆ’12+12=āˆ’42+12 ⇒ 6x=āˆ’306x - 12 + 12 = -42 + 12 \ \Rightarrow\ 6x = -30
  3. 3

    Divide both sides by 6:

    6x6=āˆ’306 ⇒ x=āˆ’5\frac{6x}{6} = \frac{-30}{6} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    6ā‹…(āˆ’5)āˆ’12=āˆ’30āˆ’12=āˆ’42āœ“6\cdot(-5) - 12 = -30 - 12 = -42 \checkmark
LaTeX source of the formulas on this page
\[ 6x - 12 = -42\ \Rightarrow\ x = -5 \]
\[ 6x - 12 = -42 \]
\[ 6x - 12 + 12 = -42 + 12 \ \Rightarrow\ 6x = -30 \]
\[ \frac{6x}{6} = \frac{-30}{6} \ \Rightarrow\ x = -5 \]
\[ 6\cdot(-5) - 12 = -30 - 12 = -42 \checkmark \]

Trying values of x in 6x āˆ’ 12 = āˆ’42

x6x āˆ’ 12Equals -42?
-7-54no
-6-48no
-5-42yes
-4-36no
-3-30no

Questions

What is x in 6x āˆ’ 12 = āˆ’42?

The solution of 6x āˆ’ 12 = āˆ’42 is x = -5.

How do you solve 6x āˆ’ 12 = āˆ’42?

Add 12 to both sides to get 6x = -30, then divide both sides by 6 to get x = -5.

How do I check the answer?

Replace x by -5: 6(-5) āˆ’ 12 = -42, which is -42.

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    Solve 6x āˆ’ 12 = āˆ’42: x = -5 (steps and check) | WordGPT