Solve 6x ā 12 = 78
The solution of 6x ā 12 = 78 is x = 15.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 12 to both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = 15 back into the equation.
LaTeX source of the formulas on this page
\[ 6x - 12 = 78\ \Rightarrow\ x = 15 \]
\[ 6x - 12 = 78 \]
\[ 6x - 12 + 12 = 78 + 12 \ \Rightarrow\ 6x = 90 \]
\[ \frac{6x}{6} = \frac{90}{6} \ \Rightarrow\ x = 15 \]
\[ 6\cdot15 - 12 = 90 - 12 = 78 \checkmark \]Trying values of x in 6x ā 12 = 78
| x | 6x ā 12 | Equals 78? |
|---|---|---|
| 13 | 66 | no |
| 14 | 72 | no |
| 15 | 78 | yes |
| 16 | 84 | no |
| 17 | 90 | no |
Questions
What is x in 6x ā 12 = 78?
The solution of 6x ā 12 = 78 is x = 15.
How do you solve 6x ā 12 = 78?
Add 12 to both sides to get 6x = 90, then divide both sides by 6 to get x = 15.
How do I check the answer?
Replace x by 15: 6(15) ā 12 = 78, which is 78.