Solve 6x ā 11 = ā47
The solution of 6x ā 11 = ā47 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 11 to both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 6x - 11 = -47\ \Rightarrow\ x = -6 \]
\[ 6x - 11 = -47 \]
\[ 6x - 11 + 11 = -47 + 11 \ \Rightarrow\ 6x = -36 \]
\[ \frac{6x}{6} = \frac{-36}{6} \ \Rightarrow\ x = -6 \]
\[ 6\cdot(-6) - 11 = -36 - 11 = -47 \checkmark \]Trying values of x in 6x ā 11 = ā47
| x | 6x ā 11 | Equals -47? |
|---|---|---|
| -8 | -59 | no |
| -7 | -53 | no |
| -6 | -47 | yes |
| -5 | -41 | no |
| -4 | -35 | no |
Questions
What is x in 6x ā 11 = ā47?
The solution of 6x ā 11 = ā47 is x = -6.
How do you solve 6x ā 11 = ā47?
Add 11 to both sides to get 6x = -36, then divide both sides by 6 to get x = -6.
How do I check the answer?
Replace x by -6: 6(-6) ā 11 = -47, which is -47.