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Solve 6x āˆ’ 11 = 19

The solution of 6x āˆ’ 11 = 19 is x = 5.

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The lines y = 6x āˆ’ 11 and y = 19 meet at x = 5246810-20-10102030405060x = 5y = 6x āˆ’ 11y = 19
The lines y = 6x āˆ’ 11 and y = 19 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    6xāˆ’11=196x - 11 = 19
  2. 2

    Add 11 to both sides:

    6xāˆ’11+11=19+11Ā ā‡’Ā 6x=306x - 11 + 11 = 19 + 11 \ \Rightarrow\ 6x = 30
  3. 3

    Divide both sides by 6:

    6x6=306Ā ā‡’Ā x=5\frac{6x}{6} = \frac{30}{6} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    6ā‹…5āˆ’11=30āˆ’11=19āœ“6\cdot5 - 11 = 30 - 11 = 19 \checkmark
LaTeX source of the formulas on this page
\[ 6x - 11 = 19\ \Rightarrow\ x = 5 \]
\[ 6x - 11 = 19 \]
\[ 6x - 11 + 11 = 19 + 11 \ \Rightarrow\ 6x = 30 \]
\[ \frac{6x}{6} = \frac{30}{6} \ \Rightarrow\ x = 5 \]
\[ 6\cdot5 - 11 = 30 - 11 = 19 \checkmark \]

Trying values of x in 6x āˆ’ 11 = 19

x6x āˆ’ 11Equals 19?
37no
413no
519yes
625no
731no

Questions

What is x in 6x āˆ’ 11 = 19?

The solution of 6x āˆ’ 11 = 19 is x = 5.

How do you solve 6x āˆ’ 11 = 19?

Add 11 to both sides to get 6x = 30, then divide both sides by 6 to get x = 5.

How do I check the answer?

Replace x by 5: 6(5) āˆ’ 11 = 19, which is 19.

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