Solve 6x ā 10 = 32
The solution of 6x ā 10 = 32 is x = 7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 10 to both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = 7 back into the equation.
LaTeX source of the formulas on this page
\[ 6x - 10 = 32\ \Rightarrow\ x = 7 \]
\[ 6x - 10 = 32 \]
\[ 6x - 10 + 10 = 32 + 10 \ \Rightarrow\ 6x = 42 \]
\[ \frac{6x}{6} = \frac{42}{6} \ \Rightarrow\ x = 7 \]
\[ 6\cdot7 - 10 = 42 - 10 = 32 \checkmark \]Trying values of x in 6x ā 10 = 32
| x | 6x ā 10 | Equals 32? |
|---|---|---|
| 5 | 20 | no |
| 6 | 26 | no |
| 7 | 32 | yes |
| 8 | 38 | no |
| 9 | 44 | no |
Questions
What is x in 6x ā 10 = 32?
The solution of 6x ā 10 = 32 is x = 7.
How do you solve 6x ā 10 = 32?
Add 10 to both sides to get 6x = 42, then divide both sides by 6 to get x = 7.
How do I check the answer?
Replace x by 7: 6(7) ā 10 = 32, which is 32.