Solve 5x + 9 = ā41
The solution of 5x + 9 = ā41 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 9 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 9 = -41\ \Rightarrow\ x = -10 \]
\[ 5x + 9 = -41 \]
\[ 5x + 9 - 9 = -41 - 9 \ \Rightarrow\ 5x = -50 \]
\[ \frac{5x}{5} = \frac{-50}{5} \ \Rightarrow\ x = -10 \]
\[ 5\cdot(-10) + 9 = -50 + 9 = -41 \checkmark \]Trying values of x in 5x + 9 = ā41
| x | 5x + 9 | Equals -41? |
|---|---|---|
| -12 | -51 | no |
| -11 | -46 | no |
| -10 | -41 | yes |
| -9 | -36 | no |
| -8 | -31 | no |
Questions
What is x in 5x + 9 = ā41?
The solution of 5x + 9 = ā41 is x = -10.
How do you solve 5x + 9 = ā41?
Subtract 9 from both sides to get 5x = -50, then divide both sides by 5 to get x = -10.
How do I check the answer?
Replace x by -10: 5(-10) + 9 = -41, which is -41.