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Solve 5x + 5 = āˆ’20

The solution of 5x + 5 = āˆ’20 is x = -5.

The lines y = 5x + 5 and y = -20 meet at x = -5-10-8-6-4-2-50-40-30-20-1010x = -5y = 5x + 5y = -20
The lines y = 5x + 5 and y = -20 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    5x+5=āˆ’205x + 5 = -20
  2. 2

    Subtract 5 from both sides:

    5x+5āˆ’5=āˆ’20āˆ’5 ⇒ 5x=āˆ’255x + 5 - 5 = -20 - 5 \ \Rightarrow\ 5x = -25
  3. 3

    Divide both sides by 5:

    5x5=āˆ’255 ⇒ x=āˆ’5\frac{5x}{5} = \frac{-25}{5} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    5ā‹…(āˆ’5)+5=āˆ’25+5=āˆ’20āœ“5\cdot(-5) + 5 = -25 + 5 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 5x + 5 = -20\ \Rightarrow\ x = -5 \]
\[ 5x + 5 = -20 \]
\[ 5x + 5 - 5 = -20 - 5 \ \Rightarrow\ 5x = -25 \]
\[ \frac{5x}{5} = \frac{-25}{5} \ \Rightarrow\ x = -5 \]
\[ 5\cdot(-5) + 5 = -25 + 5 = -20 \checkmark \]

Trying values of x in 5x + 5 = āˆ’20

x5x + 5Equals -20?
-7-30no
-6-25no
-5-20yes
-4-15no
-3-10no

Questions

What is x in 5x + 5 = āˆ’20?

The solution of 5x + 5 = āˆ’20 is x = -5.

How do you solve 5x + 5 = āˆ’20?

Subtract 5 from both sides to get 5x = -25, then divide both sides by 5 to get x = -5.

How do I check the answer?

Replace x by -5: 5(-5) + 5 = -20, which is -20.

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    Solve 5x + 5 = āˆ’20: x = -5 (steps and check) | WordGPT