Solve 5x + 2 = ā33
The solution of 5x + 2 = ā33 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 2 = -33\ \Rightarrow\ x = -7 \]
\[ 5x + 2 = -33 \]
\[ 5x + 2 - 2 = -33 - 2 \ \Rightarrow\ 5x = -35 \]
\[ \frac{5x}{5} = \frac{-35}{5} \ \Rightarrow\ x = -7 \]
\[ 5\cdot(-7) + 2 = -35 + 2 = -33 \checkmark \]Trying values of x in 5x + 2 = ā33
| x | 5x + 2 | Equals -33? |
|---|---|---|
| -9 | -43 | no |
| -8 | -38 | no |
| -7 | -33 | yes |
| -6 | -28 | no |
| -5 | -23 | no |
Questions
What is x in 5x + 2 = ā33?
The solution of 5x + 2 = ā33 is x = -7.
How do you solve 5x + 2 = ā33?
Subtract 2 from both sides to get 5x = -35, then divide both sides by 5 to get x = -7.
How do I check the answer?
Replace x by -7: 5(-7) + 2 = -33, which is -33.