Solve 5x + 2 = 47
The solution of 5x + 2 = 47 is x = 9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = 9 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 2 = 47\ \Rightarrow\ x = 9 \]
\[ 5x + 2 = 47 \]
\[ 5x + 2 - 2 = 47 - 2 \ \Rightarrow\ 5x = 45 \]
\[ \frac{5x}{5} = \frac{45}{5} \ \Rightarrow\ x = 9 \]
\[ 5\cdot9 + 2 = 45 + 2 = 47 \checkmark \]Trying values of x in 5x + 2 = 47
| x | 5x + 2 | Equals 47? |
|---|---|---|
| 7 | 37 | no |
| 8 | 42 | no |
| 9 | 47 | yes |
| 10 | 52 | no |
| 11 | 57 | no |
Questions
What is x in 5x + 2 = 47?
The solution of 5x + 2 = 47 is x = 9.
How do you solve 5x + 2 = 47?
Subtract 2 from both sides to get 5x = 45, then divide both sides by 5 to get x = 9.
How do I check the answer?
Replace x by 9: 5(9) + 2 = 47, which is 47.