Solve 5x + 10 = ā40
The solution of 5x + 10 = ā40 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 10 = -40\ \Rightarrow\ x = -10 \]
\[ 5x + 10 = -40 \]
\[ 5x + 10 - 10 = -40 - 10 \ \Rightarrow\ 5x = -50 \]
\[ \frac{5x}{5} = \frac{-50}{5} \ \Rightarrow\ x = -10 \]
\[ 5\cdot(-10) + 10 = -50 + 10 = -40 \checkmark \]Trying values of x in 5x + 10 = ā40
| x | 5x + 10 | Equals -40? |
|---|---|---|
| -12 | -50 | no |
| -11 | -45 | no |
| -10 | -40 | yes |
| -9 | -35 | no |
| -8 | -30 | no |
Questions
What is x in 5x + 10 = ā40?
The solution of 5x + 10 = ā40 is x = -10.
How do you solve 5x + 10 = ā40?
Subtract 10 from both sides to get 5x = -50, then divide both sides by 5 to get x = -10.
How do I check the answer?
Replace x by -10: 5(-10) + 10 = -40, which is -40.