Solve 5x + 1 = ā19
The solution of 5x + 1 = ā19 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 1 = -19\ \Rightarrow\ x = -4 \]
\[ 5x + 1 = -19 \]
\[ 5x + 1 - 1 = -19 - 1 \ \Rightarrow\ 5x = -20 \]
\[ \frac{5x}{5} = \frac{-20}{5} \ \Rightarrow\ x = -4 \]
\[ 5\cdot(-4) + 1 = -20 + 1 = -19 \checkmark \]Trying values of x in 5x + 1 = ā19
| x | 5x + 1 | Equals -19? |
|---|---|---|
| -6 | -29 | no |
| -5 | -24 | no |
| -4 | -19 | yes |
| -3 | -14 | no |
| -2 | -9 | no |
Questions
What is x in 5x + 1 = ā19?
The solution of 5x + 1 = ā19 is x = -4.
How do you solve 5x + 1 = ā19?
Subtract 1 from both sides to get 5x = -20, then divide both sides by 5 to get x = -4.
How do I check the answer?
Replace x by -4: 5(-4) + 1 = -19, which is -19.