Solve 5x + 1 = 21
The solution of 5x + 1 = 21 is x = 4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = 4 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 1 = 21\ \Rightarrow\ x = 4 \]
\[ 5x + 1 = 21 \]
\[ 5x + 1 - 1 = 21 - 1 \ \Rightarrow\ 5x = 20 \]
\[ \frac{5x}{5} = \frac{20}{5} \ \Rightarrow\ x = 4 \]
\[ 5\cdot4 + 1 = 20 + 1 = 21 \checkmark \]Trying values of x in 5x + 1 = 21
| x | 5x + 1 | Equals 21? |
|---|---|---|
| 2 | 11 | no |
| 3 | 16 | no |
| 4 | 21 | yes |
| 5 | 26 | no |
| 6 | 31 | no |
Questions
What is x in 5x + 1 = 21?
The solution of 5x + 1 = 21 is x = 4.
How do you solve 5x + 1 = 21?
Subtract 1 from both sides to get 5x = 20, then divide both sides by 5 to get x = 4.
How do I check the answer?
Replace x by 4: 5(4) + 1 = 21, which is 21.